The diameter of the circle (O), (XY) is 12cm.

Two adjacent vertices of the square (ABCD) lie on the diameter of that circle, while the other two vertices lie on the circumference of the circle.

What is the length of a diagonal of this square (DB)?

I considered the triangle, ABO, with its sides AO and BO at 6cm. Therefore, AB (and each side of the square) equal to ~8.49cm. From this I used a2+b2=c2 to get the diagonal roughly 11.9cm. Obviously this is wrong but is the logic wrong, where did I fail?

Posted by Jimmy Bob on 2002-12-06 13:25:33