All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Circles Abound (2) (Posted on 2004-10-17) Difficulty: 4 of 5
I've a black circle of radius 5.

I wish to create 5 identical white circles of some lesser radius, which I will place on top of the black circle and completely obscure (cover) the black circle.

What is the smallest radius which I can make the smaller circles and still meet my requirement?

No Solution Yet Submitted by SilverKnight    
Rating: 3.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Phi Again | Comment 7 of 12 |

Gosh! So, what have I learned so far?

Okay. Charlie had the answer all along. Richard knew there was a simple constant and knew the history of the problem. Also he knows a bunch of secret website information. Cee? Well, nice try Cee. Nikki got the answer too, but made it a lot more clear. Well, to me anyway.

So, we merely needed to multiply the radius of the black circle by the reciprocal of phi to find the radius of the white circles we need to use. 5 times 0.618033988 = 3.09016994.

Wow! The Golden Ratio strikes again.


  Posted by CeeAnne on 2004-10-19 04:46:19
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information