Last digits of powers of 11 is all 1.
Last digits of powers of 7 is 7, 9, 3, 1 and then repeats.
Last digits of powers of 13 is 3, 9, 7, 1 and then repeats.
2004 is 0 mod 4, and 2005 is 1 mod 4.
So the last digits of 11^2003 is 1 and the last digits of 7^2004 is 1 and the last digit of 13^2005 is 3. Therefore, the last digit of the product is 3.
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Posted by doremi
on 2004-10-29 20:34:01 |