Find all integers 1<=k<=169 for which 169 is not the sum of k nonzero squares.
The squares are not necessarily unique. For example k=5: 169=1+4+4+16+144.
This should be done without a brute force program.
Nobody was posting any comments on here, so I thought I would start, even if I had little idea what I was doing. So here goes:
The square numbers (that pertain to this problem) are: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169.
25 can be written as 9 + 16 because 3^2 + 4^2 = 5^2. It is a pythagorean triple. 100 = 64 + 36. 169 = 144 + 25.
Perhaps this problem has something to do with pythagorean triples. There are even other sums besides those. 9 = 4 + 4 + 1. I don't know.
I hope this helps someone else get an idea and run with it.
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Posted by Dustin
on 2004-11-04 21:20:34 |