If two 1's, two 2's and two 3's are arranged thus:
2 3 1 2 1 3
then the two 1's enclose 1 other digit, the two 2's enclose 2 other digits, and the two 3's enclose 3 other digits.
Can you
find a similar arrangement using the seven pairs 1,1,...7,7?
72462354736151
There's my solution. I found it easier to put the 14 blank spaces on a sheet of paper, and start with the 7's and work my way down. I'm sure this is not the only solution. I haven't read any comments yet. One trivial extra solution is just to turn it around. One seems plenty. :)
|
Posted by Michael
on 2004-11-29 04:42:55 |