1. Find the ellipse of smallest area which circumscribes 2 non-overlapping unit circles.
2. Find the ellipse of smallest area which circumscribes 3 non-overlapping unit circles.
(In reply to
re: As far as I plan to get [I'm silly!] by Jer)
Ok, so I went and took the derivative of the expression from my last post. When I set it equal to zero, a lot simplified.
The solution for b is the positive root of b^3 + b^2 - 2b - 1 =0
-Jer
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Posted by Jer
on 2004-11-30 18:52:44 |