I present to you a deck of 4 cards. Each card has on one side a letter of the alphabet, and on the other side a single digit from 0-9.
I propose a hypothesis that may apply to this deck:
If the letter is 'E', then the number on the other side is '4'.
I then drop the 4 cards on the table, and you see:
'B', '7', 'E', '4' (on the respective cards).
Which of the 4 cards must you turn over to verify or disprove my hypothesis?
You must turn over 7 and E.
"If X, then Y" is false if X is true and Y is false. It is true for all other conditions. X="card has E" and Y="card has 4".
X is true, Y is false if and only if some card with E has a number other than 4 on the other side.
If 7 has an E on the other side, or if E has a number other than 4 on the other side, the hypothesis is disproved. Otherwise it is proved for the 4 card deck.
I originally said you had to turn over 4. I realized that was incorrect after reading Nikki's post.
If 4 has an E on the other side, that is "X is true, Y is true." Irrelevant.
If 4 has a T on the other side, that is "X is false, Y is true." Irrelevant.
If B has a 4 on the other side, that is "X is false, Y is true". Irrelevant.
If B has a 2 on the other side, that is "X is false, Y is false". Irrelevant.
Edited on December 15, 2004, 3:32 pm
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Posted by Penny
on 2004-12-15 15:14:04 |