All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Sphere Pyramid (Posted on 2005-01-19) Difficulty: 3 of 5
You may find the Sphere Cube problem to be similar.

Four identical spheres (like the ones shown in blue in the above cube case) are arranged in a pyramid, such that each sphere is tangent to the other three. If the radius of the four spheres is R, what is the radius r of the largest sphere (such as the one shown in red on the cube picture) that could exist inside the pyramid without overlapping the other spheres?

See The Solution Submitted by nikki    
Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 1 of 4

The centers of the four spheres form the vertices of a regular tetrahedron of side length 2R, so we may place them on the vertices (x,x,x), (x,-x,-x), (-x,x,-x), and (-x,-x,x) of the cube of side length 2x where x = R*sqrt(2)/2. 

The desired radius is then the distance from the center (0,0,0) of the cube to a vertex, minus R.  So we have

r = x*sqrt(3)-R
  = R(sqrt(6)/2 - 1).


  Posted by David Shin on 2005-01-19 18:31:31
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information