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Ice Floating in Water (Posted on 2005-04-21) Difficulty: 3 of 5

You have a cube of ice floating in a glass of water. The question is what fraction of the ice will be above the water line? Assume that the ice is not bobbing.

Most of you have probably heard the answer to this before. But please provide a proof or solution, along with your assumptions.

See The Solution Submitted by np_rt    
Rating: 3.0000 (8 votes)

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Solution J.C. won't like this | Comment 24 of 31 |

I shall first give my answer,and then give some juicy remarks about a guy who's spamming up this site.

For convenience's sake,let us assume that ice is in equilibrium with water(and I ain't doing a big research project on what kind of water that is).In that case,amount of ice melted=amount of ice formed.

Let the volume of the ice cube be V,volume submerged beV'

If d be the relative density of ice, g be acceleration due to gravity,then

           Vdg=V'g

or,       Vd=V'

           V'/V=d

          V'-V/V=d-1

         V-V'/V= 1-d

and thus is my answer.

By,the way, has anyone noticed that 14 of the 23 comments posted are from some guy who's under the delusion that he's brainy?And that all his dumb,idiotic and pointless comments just say the same thing?Get real,Jonathan Chang,and do not act like you never studied physics in your life.If you've got any grey stuff in your cranium,work out a solution for all those suppositions you made , and then post a comment.

You gave np_rt an excuse that you couldn't find the densities of all the waters in the world,so for heaven's sake assume them to be d1,d2,d3,and so on.BUT JUST DO SOMETHING.

P.S:-If you like to apologise so much(see the chatterbox,he's spammed that too),say sorry for spamming this comment list. 


  Posted by Rex on 2005-04-22 14:45:37
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