All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Algorithms
Towers of Hanoi variation (Posted on 2005-05-03) Difficulty: 3 of 5
There are some poles, and on the first pole are some rings, each a different size. The sizes of the rings increases from the top to the bottom of the pole. The only allowable move is to take the top ring from any pole and place onto another pole. You cannot place a ring on top of another ring unless the other ring is exactly one size bigger. You can make as many moves as you like.

Your goal is to move all the rings onto the second pole, in the same order. What is the highest number of rings that can be moved when there are N poles? How can you move this many rings?

See The Solution Submitted by Tristan    
Rating: 4.0000 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 8 of 15 |

My answers follow a pattern of

2^(N-1) - 1

So for N= 1, 2, 3, 4, 5, 6 poles I can move

0, 1, 3, 7, 15, 31 . . .

Which is also equal to: when a pole is added, twice as many rings can be moved plus one.  

Edited on May 3, 2005, 6:20 pm
  Posted by Leming on 2005-05-03 18:20:21

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information