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Create the equation (Posted on 2005-05-09) Difficulty: 2 of 5
One solution of the equation (x-a)(x-b)(x-c)(x-d)=25 is x=7.

If a, b, c, and d are different integers, find the value of a+b+c+d

See The Solution Submitted by Jer    
Rating: 2.4286 (7 votes)

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Solution Morning puzzle | Comment 1 of 10

If a,b,c,d are all different integers, then so are (x-a), (x-b), (x-c), and (x-d).

If their product is 25, they can only be 5, 1, -1, and -5, since these are the only integral factors of 25.

That means a=2, b=6, c=8, d=12 and a+b+c+d=28


  Posted by TomM on 2005-05-09 10:50:08
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