We have a billiard table in the shape of a right triangle ABC with B the right angle. A cue ball is struck at vertex A and bounces off sides BC, AC, AB, and AC at points D, E, F, and G respectively ending up at vertex B. Assume the angle of incidence equals the angle of reflection at each bounce. If the path segments AD, EF, and GB are concurrent, then what is the tangent of angle BAD?
(In reply to
re: My Efforts by Jer)
Aha! I was using an isoceles right triangle!
For θ < π:
sin θ
θ (BAD) = ----------------
cos θ - cos 4θ
That's what I think the answer is. Granted, I relearned a bit of
trigonometry in the interim, the solution may not expressed correctly.
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Posted by Charley
on 2005-05-12 20:21:42 |
re(2): My Efforts
