Place the numbers 1 through 9 in the grid below:
1 2 3
A |_|_|_|
B |_|_|_|
C |_|_|_|
- The product of the numbers in row C is twice the sum of the numbers in row C.
- The product of the numbers in column 3 is twice the sum of the numbers in column 3.
- If you ignore column 1, all the columns have even products.
- If you take the six-digit number C3 B3 B1 C1 A3 B2 and multiply it by 3, you get the six-digit number B3 B1 C1 A3 B2 C3.
Try to figure it out without using a computer program.
(In reply to
solution - spoiler by pcbouhid)
The answer is
A1 = 6 A2 = 9 A3 = 5
B1 = 2 B2 = 7 B3 = 4
C1 = 8 C2 = 3 C3 = 1
Once you find the numbers in row c and column 3 it is all about finding the order. 1 is obviously the corner which means the only possible solution for B2 is 7, since the c3b3b1c1a3b2 combo will have to be multiplied by 3. After you realize that you only have to arrange A1 and B1 correctly, because A2 is irrelevant.
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Posted by Richard
on 2005-05-18 16:35:32 |
Got it
