Place the numbers 1 through 9 in the grid below:
1 2 3
A |_|_|_|
B |_|_|_|
C |_|_|_|
- The product of the numbers in row C is twice the sum of the numbers in row C.
- The product of the numbers in column 3 is twice the sum of the numbers in column 3.
- If you ignore column 1, all the columns have even products.
- If you take the six-digit number C3 B3 B1 C1 A3 B2 and multiply it by 3, you get the six-digit number B3 B1 C1 A3 B2 C3.
Try to figure it out without using a computer program.
(In reply to
re(2): Flaw in the problem by Rupesh Khandelwal)
Rupesh,
What you wrongly implied from (3) is a common mistake, and I think that Dustin just added "if you ignore column (1)" to function as a trick. "Ignore" doesn't say nothing !!!
Those who works with dedutive logic knows that "If A then B", only, does not imply that "If not A, not B". Fot this, it is necessary to say "If A then B, otherwise C".
So, what we only extract from (3) is that columns (2) and (3) sums up to an even number. The rest is a trick !
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Posted by pcbouhid
on 2005-05-21 20:27:01 |
re(3): Flaw in the problem
