In the famous "The Odd Coin" problem you are given twelve coins, exactly one of which is lighter or heavier than the other coins. You are to determine the counterfeit coin, and whether it is lighter or heavier than the other coins, in just three weighings with a balance.

Can you solve this problem with the additional restriction that you must decide what coins go on each pan for all three weighings before any weighing takes place?

(In reply to re(3): Another way to answer it by Ken Haley)

Nice way to avoid the table!  My solution is now no better than yours, just different.

Posted by McWorter on 2005-06-07 15:45:50