Given p(1), find any power of ten greater than p(1)
--T=10^k>p(1)-- and ask for p(1/T). The desired coefficients
will appear in the result.
With
Eric's example (5x²+6x+2) we could have T=100, so we'd ask for
p(0.01)=2.0605 and the coefficients are in plain sight. (T=1000 would
ask for p(0.001)=2.006005)