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Unusual binary representation (Posted on 2005-06-14) Difficulty: 3 of 5
Show that every positive integer is an alternating sum of strictly increasing powers of 2.

For example, 5=2^0 -2^2 +2^3 and 8=-2^3 +2^4 are alternating sums of strictly increasing powers of 2 (8=2^3 is ok too).

10=-2^1 -2^2 +2^4 is a strictly increasing sum but not alternating.

4=2^1 -2^1 +2^2 is alternating but not strictly increasing.

(author: prof Dan Shapiro of Ohio State University)

See The Solution Submitted by McWorter    
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re(2): Negabinary | Comment 5 of 9 |
(In reply to re: Negabinary by Old Original Oskar!)

You are right if zero coefficents are disallowed.  But (-2)^n does alternate and its sign can be stolen and given instead to the 1 or 0 coefficients of the negabinary number, so if 0 coefficients are allowed, then you get an alternating representation of the form

b_0*2^0 - b_1*2^1 + b_2*2^2 - ...

where the b_i are unique coefficients, 1 or 0. You can make a good case, however, that allowing 0's is a underhanded way to destroy the purity of alternatingness.


  Posted by Richard on 2005-06-15 01:48:53
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