One solution of the equation
(x-a)(x-b)(x-c)(x-d)=25
is x=7.
If a, b, c, and d are different integers, find the value of a+b+c+d
this can b solved by an eighth grade student
ofcourse if a,b,c,d are all integers so are 7-a,7-b,7-c and 7-d
further to get product of four integers as 25 with all a,b,c,d being distinct can only be
a,b,c,d = 6,8,12,2 (map ne 1 with ne 1 )
-1 x 1 x -5 x 5 =25
by the way sum is 28 , grrrrrrr real time waste
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Posted by phi
on 2005-06-22 07:56:45 |