You have nine brass rings, but three are actually gold. Can you pick these out using a balance scale three times at the most?
I introduced a idea of rotating objects one at a time; arose from shifting 'bits' within a 'byte' through a 'circular' motion.
(Ring Around comments refer to this.)
After Charlie's comment (The answer is .. and my follow-up omment re: The answer is ...) I have rethought.
Currently I do not have the time to explore this fully, but offer it as a means to a +ve or -ve solution.
Again I am presuming which are the Gold. I am now suggesting
GroupA and GroupB hold 4 rings while GroupC (Table) has only 1.
Test# GroupA GroupB GroupC Result
1 GGG4
5678
9
Heavy left - no other validity.
2 9GGG
4567
8
Heavy left - ?????
3 89GG
G456
7
Still Heavy Left - ??!!??
I have a sense that if I analysed what the potential elements could
have been, rather that my 'precast' arangement, there may be a solution.
|
Posted by brianjn
on 2005-06-26 04:20:04 |