Find the rule and continue this sequence of digits:
1235813941213533488671216141383377554...
Is there a limit to the number of times in a row a digit can appear?
1235813941213533488671216141383377554... the sequence in continuation will be 111161014121095 ....its easy folks so i m not disclosing how i did it , u try
a hint : its actually 11 11 6 10 14 12 10 9 5 ..... (ring any bells )
still dont get it .... well 1+2=3 2+3=5 3+5=8 5+8=13 8+1=9 1+3=4 ....and so on now c'mon dnt say still dnt get it ..lol
the second part ...hmm i dnt get it Jer frankly lets see single digit additions cant produce repeated digits xcept 11 bcoz they certainly cant add up to 22 it will be less than equal to 18 (9+9 as max) again it may only be so that atmost both consecutive additions yield 11 like the start of our solution (3,8) and (8,3) .... which gets 4 consecutive 1's .... i know one thing for sure no other digit xcept 1 can be repeated more than 3 times
|
Posted by phi
on 2005-06-28 07:37:23 |