Suppose you have a circle that is perfectly inscribed in a rectangle.
A smaller rectangle is placed on top of the first one, such that one corner is on the edge of the circle and the opposite corner matches a corner of the larger rectangle.

If the smaller rectangle is twice as long as it is high, how many of them will fit into of the larger one (without overlapping, of course)?

Precisely 50 of the rectangles will fit into the square.

Edited on March 25, 2007, 11:11 am

Posted by K Sengupta on 2005-07-05 07:27:16