The goal is to continue a perspective drawing of a floor tiled with congruent square tiles. Specifically, let XY be a horizontal line representing the horizon of the perspective drawing. Let ABCD be one of the square tiles in the foreground, with A nearest the viewer, B on the line XA, D on the line YA, and C the intersection of lines XD and YB. Show how to construct the tile next to ABCD with side BC in common with tile ABCD.

I happen to be taking an art class, so, here goes:

D______________C__________F
/ \ \
/ \ \
/ \ \
A------------------B-------------E

That's not a really good representation of it...but
because it is a perspective drawing, everything starts
on the same horizon (XY), which I didn't really shows.
That's why BE is a continuation of AB. And because the
tiles are congruent they will go the same distance back.
That is why CF is a continuation of DC. The tricky part
is how to do the second line, the one across from CB, in
this drawing, line FE. It simply has to be at a sharper
angle than line CB. This doesn't really look like the
drawing I made on my paper, but I think that's the idea.
Or at least, I hope I understood the problem correctly.

Posted by Emily on 2005-08-27 15:27:10