The goal is to continue a perspective drawing of a floor tiled with congruent square tiles. Specifically, let XY be a horizontal line representing the horizon of the perspective drawing. Let ABCD be one of the square tiles in the foreground, with A nearest the viewer, B on the line XA, D on the line YA, and C the intersection of lines XD and YB. Show how to construct the tile next to ABCD with side BC in common with tile ABCD.

(In reply to No Subject by Ken Haley)

Wow!  Bractals and Ken give two different solutions, and both different from mine!  (My solution is slightly shorter than Bractals')

Posted by McWorter on 2005-08-27 19:15:29