Starting from an arbitrary prime of 3 digits you choose, construct a sequence of distinct 3-digit primes such that every one is formed by the 2 rightmost digits of the previous one plus any digit juxtaposed to the right - e.g. 113, 137, 373,... What is the maximum number of distinct primes that YOU can achieve in the sequence?

(In reply to 1820 computer solutions by Charlie)

Well, only about 1/3 of them fit, but you get the idea.  These are the largest and have 26 primes each.

Posted by Charlie on 2005-09-01 14:20:30