There are 8 people that need to cross a river. The water is too deep and fast to walk or swim across, and the only transportation device available is a raft. The raft can only be operated by adults, cannot float across the river on its own, and can carry at most two people.
The 8 people are a juvenile delinquent, her jailer, and a dysfunctional family of six: mother, father, two sons, and two daughters. To be clear, the only adults are the jailer, the mother, and the father.
Unfortunately some people fight with each other:
The juvenile delinquent will fight with anybody if her jailer is not present.
The father fights with either daughter if the mother is not present to mediate.
The mother fights with either son if the father is not present to mediate.
How can these 8 people cross the river without any fights? How many trips on the raft did it take?
For a fun way to test out your theories, click here and then click on the blue circle.
(In reply to
re: Finally--a computer solution--bug by Charlie)
The fixed program produces:
9 Jj DFJMSdjs
8 Js J Jj DFMSds
7 FS Jj Jjs DFMSd
6 FM F FSs DJMdj
5 Jj M FMSs DJdj
4 FM F FJSjs DMd
3 Md M FJMSjs Dd
2 DJ jJ FJMSdjs D
1 Jj J DFJMSds j
Where, again, the sequence is from bottom to top, so follow the numbers in that direction. Each row represents a round trip except for row 9 at the top, so this is indeed 2*8+1=17 rides across the river. F and M are the father and mother; J is the jailer and j is the j.d.; S and D are the elder son and daughter and s and d are the younger son and daughter.
The columns are the sequence number, the travelers for the outgoing trip and then the trip back, and the resulting sets of people still on the first side and then the second side.
DECLARE FUNCTION btcompat# (s$)
DECLARE SUB getRec (s$, row#, col#)
DECLARE SUB putRec (s$, row#, col#)
DECLARE FUNCTION compat# (s$)
DECLARE FUNCTION number# (s$)
DEFDBL A-Z
CLS
DIM SHARED template$
template$ = "DFJMSdjs" ' Dgtr1,Father,Jailer,Mother,Son1,Dgtr2,JD,Son2
DIM side1$(256), side2$(256)
OPEN "dyscros2.bin" FOR BINARY AS #2
' at 4 bytes per cell, a 256x256 matrix takes up 262,144 bytes
' first and second = boat rider(s)'s letter(s)
' third and fourth = return boat rider(s)'s letter(s)
s4$ = " "
FOR i = 0 TO 255
FOR j = 0 TO 255
PUT #2, , s4$
NEXT
NEXT
FOR n = 0 TO 255
s1$ = template$: s2$ = ""
i = n: p = 8
DO
r = i MOD 2: i = i \ 2
IF r = 0 THEN
MID$(s1$, p, 1) = " "
s2$ = MID$(template$, p, 1) + s2$
END IF
p = p - 1
LOOP UNTIL p = 0
DO
ix = INSTR(s1$, " ")
IF ix THEN s1$ = LEFT$(s1$, ix - 1) + MID$(s1$, ix + 1)
LOOP UNTIL ix = 0
side1$(n) = s1$: side2$(n) = s2$
' PRINT n; TAB(15); s1$; TAB(30); s2$
' IF n MOD 40 = 0 THEN DO: LOOP UNTIL INKEY$ > ""
NEXT
'build transition matrix
FOR start = 0 TO 255
s1$ = side1$(start): s2$ = side2$(start)
IF compat(s1$) AND compat(s2$) THEN
FOR i = 1 TO LEN(s1$)
bt$ = MID$(s1$, i, 1) + " "
newS2$ = RTRIM$(s2$ + bt$)
newS1$ = LEFT$(s1$, i - 1) + MID$(s1$, i + 1)
IF btcompat(bt$) AND compat(newS2$) AND compat(newS1$) THEN
newNum = number(newS1$)
getRec chk$, start, newNum
IF chk$ < "A" THEN
putRec bt$, start, newNum
END IF
' figure return trip
FOR k = 1 TO LEN(newS2$)
bt2$ = MID$(newS2$, k, 1) + " "
newerS1$ = RTRIM$(newS1$ + bt2$)
newerS2$ = LEFT$(newS2$, k - 1) + MID$(newS2$, k + 1)
IF compat(newerS1$) AND compat(newerS2$) AND btcompat(bt2$) THEN
newerNum = number(newerS1$)
getRec chk$, start, newerNum
IF MID$(chk$, 3, 2) < "A" THEN
putRec bt$ + bt2$, start, newerNum
END IF
END IF
FOR l = k + 1 TO LEN(newS2$)
MID$(bt2$, 2, 1) = MID$(newS2$, l, 1)
newerS1$ = RTRIM$(newS1$ + bt2$)
ix = INSTR(newerS2$, RIGHT$(bt2$, 1))
newestS2$ = LEFT$(newerS2$, ix - 1) + MID$(newerS2$, ix + 1)
IF compat(newerS1$) AND compat(newestS2$) AND btcompat(bt2$) THEN
newerNum = number(newerS1$)
getRec chk$, start, newerNum
IF MID$(chk$, 3, 2) < "A" THEN
putRec bt$ + bt2$, start, newerNum
END IF
END IF
NEXT l
NEXT k
END IF
FOR j = i + 1 TO LEN(s1$)
MID$(bt$, 2, 1) = MID$(s1$, j, 1)
newS2$ = RTRIM$(s2$ + bt$)
ix = INSTR(newS1$, RIGHT$(bt$, 1))
newerS1$ = LEFT$(newS1$, ix - 1) + MID$(newS1$, ix + 1)
IF compat(newerS1$) AND compat(newS2$) AND btcompat(bt$) THEN
newerNum = number(newerS1$)
getRec chk$, start, newerNum
IF MID$(chk$, 1, 2) < "A" THEN
putRec bt$, start, newerNum
END IF
' figure return trip
FOR k = 1 TO LEN(newS2$)
bt2$ = MID$(newS2$, k, 1) + " "
newestS1$ = RTRIM$(newerS1$ + bt2$)
newerS2$ = LEFT$(newS2$, k - 1) + MID$(newS2$, k + 1)
IF compat(newestS1$) AND compat(newerS2$) AND btcompat(bt2$) THEN
newerNum = number(newestS1$)
getRec chk$, start, newerNum
IF MID$(chk$, 3, 2) < "A" THEN
putRec bt$ + bt2$, start, newerNum
END IF
END IF
FOR l = k + 1 TO LEN(newS2$)
MID$(bt2$, 2, 1) = MID$(newS2$, l, 1)
newestS1$ = RTRIM$(newerS1$ + bt2$)
ix = INSTR(newerS2$, RIGHT$(bt2$, 1))
newestS2$ = LEFT$(newerS2$, ix - 1) + MID$(newerS2$, ix + 1)
IF compat(newerS1$) AND compat(newestS2$) AND btcompat(bt2$) THEN
newestNum = number(newestS1$)
getRec chk$, start, newestNum
IF MID$(chk$, 3, 2) < "A" THEN
putRec bt$ + bt2$, start, newestNum
END IF
END IF
NEXT l
NEXT k
END IF
NEXT
NEXT i
FOR i = 1 TO LEN(s$) - 1
FOR j = i + 1 TO LEN(s$)
NEXT
NEXT
END IF
NEXT
REM
DIM h$(30, 256)
genr = 1
FOR i = 0 TO 255
getRec s$, 255, i
IF LTRIM$(s$) > "" THEN
h$(1, i) = CHR$(255) + s$
PRINT i; s$; side2$(i)
END IF
NEXT
DO
genr = genr + 1
flag = 0
FOR dest = 0 TO 255
ps$ = h$(genr - 1, dest)
IF LTRIM$(MID$(ps$, 2, 1)) = "" OR LTRIM$(MID$(ps$, 4, 1)) = "" AND dest <> 0 THEN
FOR src = 0 TO 255
getRec s$, src, dest
IF LTRIM$(s$) > "" AND dest = 0 OR LTRIM$(MID$(s$, 3)) > "" THEN
backw = 1
DO
ps$ = h$(genr - backw, src)
IF LTRIM$(MID$(ps$, 4, 1)) = "" THEN EXIT DO
IF LTRIM$(MID$(ps$, 4, 1)) <> "-" THEN EXIT DO
backw = backw + 1
LOOP
IF LTRIM$(MID$(ps$, 4, 1)) > "" THEN
h$(genr, dest) = CHR$(src) + s$
PRINT genr; src; side1$(src); ","; side2$(src); ";"; dest; side1$(dest); ","; side2$(dest); ";"; s$
flag = 1
EXIT FOR
END IF
END IF
NEXT
ELSE
h$(genr, dest) = CHR$(dest) + "----"
END IF
NEXT
LOOP UNTIL flag = 0 OR genr > 12
PRINT genr
prv = 0
FOR i = genr TO 1 STEP -1
PRINT i; MID$(h$(i, prv), 2, 2); " "; MID$(h$(i, prv), 4, 2), side1$(prv), side2$(prv)
prv = ASC(h$(i, prv))
NEXT
CLOSE
END
FUNCTION btcompat (s$)
c = 1
IF LEN(RTRIM$(s$)) > 1 THEN
IF INSTR(s$, "j") > 0 AND INSTR(s$, "J") = 0 THEN c = 0
IF INSTR(s$, "F") > 0 AND INSTR(LCASE$(s$), "d") > 0 AND INSTR(s$, "M") = 0 THEN c = 0
IF INSTR(s$, "M") > 0 AND INSTR(LCASE$(s$), "s") > 0 AND INSTR(s$, "F") = 0 THEN c = 0
END IF
IF INSTR(s$, "F") = 0 AND INSTR(s$, "M") = 0 AND INSTR(s$, "J") = 0 THEN c = 0
btcompat = c
END FUNCTION
FUNCTION compat (s$)
c = 1
IF LEN(RTRIM$(s$)) > 1 THEN
IF INSTR(s$, "j") > 0 AND INSTR(s$, "J") = 0 THEN c = 0
IF INSTR(s$, "F") > 0 AND INSTR(LCASE$(s$), "d") > 0 AND INSTR(s$, "M") = 0 THEN c = 0
IF INSTR(s$, "M") > 0 AND INSTR(LCASE$(s$), "s") > 0 AND INSTR(s$, "F") = 0 THEN c = 0
END IF
compat = c
END FUNCTION
SUB getRec (s$, row, col)
p = row * 256 * 4 + col * 4 + 1
s$ = SPACE$(4)
GET #2, p, s$
END SUB
FUNCTION number (s$)
pow = 1
FOR p = 8 TO 1 STEP -1
IF INSTR(s$, MID$(template$, p, 1)) THEN n = n + pow
pow = pow * 2
NEXT
number = n
END FUNCTION
SUB putRec (s$, row, col)
p = row * 1024 + col * 4 + 1 ' 1024=256*4
s1$ = LEFT$(s$ + SPACE$(4), 4)
PUT #2, p, s1$
END SUB
|
Posted by Charlie
on 2005-09-28 13:54:43 |