Five children: Jane, Kevin, Leo, Mike and Nina live in the same street in consecutively numbered houses.
(Addresses do not alternate from one side of the road to another so they are all on the same side of the road).
The ages of the children are 5, 6, 9, 10 and 12 and the colours of their houses are red, yellow, green, blue and purple.

Using the following information determine each child’s information.

1.) The sum of their addresses is 55.

2.) The person who lives in the blue house has an age equal to half her address.

3.) The 9 year old lives in house No. 13.

4.) Leo’s age is the same as the number on the purple house.

5.) The colour of Jane’s house, combined with the colour of house No. 12, gives the colour of the 6 year old’s house.

6.) The Blue house is the same distance from the purple house as it is from the yellow house.

7.) 4 years ago Nina’s age was equal to twice as much as the difference between Kevin’s age (today) and the number on Mike’s house.

8.) One boy’s age is the same as his house number.

9.) The difference between Kevin and Mike’s house No.s is greater than the difference between Nina and Kevin’s age.

Mike lives in house number 9 which is purple and is 6 years old

Kevin lives in house number 12 which is red and is 12 years old

Jane lives in house number 10 which is blue and is 5 years old

Nina lives in house number 11 which is blue and is 10 years old

Leo lives in house number 13 which is green and is 9 years old

Posted by Kendall on 2005-10-14 12:14:44