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2nd difference sequence (Posted on 2005-10-22) Difficulty: 3 of 5
While working with a non-zero sequence recently, I noticed that when I found the second difference of the sequence, the result was identical to the original sequence. Specifically, the first term of the 2nd difference sequence was the same as the first term of the original sequence. And so on.
What is the limit (as n goes to infinity), of the ratio of the n-th term to the previous term?

Part 2
Another sequence has the property that each term of the 2nd difference sequence is equal to the corresponding term of the original sequence multiplied by "k", where k is a positive real number, not necessarily an integer.
For the original sequence, what is the ratio (in the limit) of the n-th term to the previous term?

Definition of 1st difference sequence:
For sequence: a(1), a(2), ..., a(n),...
1st difference is: a(2)-a(1), a(3)-a(2), ... a(n+1)-a(n),...

See The Solution Submitted by Larry    
Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution? | Comment 2 of 11 |

Any sequence (a, b, 2b, 4b, ....) works for the first part.  The ratio after the second term is therefore two.

In general a(n)=2 a(n-1)+a(n-2) (k-1) works for arbitrary values a(1),a(2), multiplier k and n>2;

What is the question?

Edited on October 23, 2005, 3:33 pm

Edited on October 23, 2005, 3:40 pm
  Posted by goFish on 2005-10-23 15:09:51

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