Let BAC be an arbitrary triangle with external squares ABIJ, BCKL, and CAMN. IBLP, KCNQ, and MAJR are parallelograms. Prove that PAQ, QBR, and RCP are isosceles right triangles.
(In reply to
re: Parting shot by Charlie)
Ha, ha; how right you are! The typo (replace L with P everywhere in the first sentence) deflects the shot a little off its mark.
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Posted by McWorter
on 2005-10-27 13:10:52 |