Find the rule behind this number sequence, and list the next three numbers:
..., 2, 23/3, 15, 121/5, 106/3, ..., ..., ...
(Hint: the first number listed is the second term of the sequence)
(In reply to
The Rule Is by Joe)
For a denominator of n, the numerator is (n-1)n(n+1)+(n-4)
Thus
(1)(2)(3)+(2-4) -> 4/2 -> 2
(2)(3)(4)+(3-4) -> 23/3
(3)(4)(5)+(4-4) -> 60/4 -> 15/2
(4)(5)(6)+(5-4) -> 121/5
(5)(6)(7)+(6-4) -> 212/6 -> 106/3
(6)(7)(8)+(7-4) -> 339/7
and so on, and as was pointed out in an earlier post
(0)(1)(2)+(1-4) -> -3/1 -> -3