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100 Chords (Posted on 2005-11-11) Difficulty: 4 of 5
The numbers 1 to 200 are randomly assigned to points on the circumfrence of a circle. The points are divided into 100 pairs, with no point in two pairs. The two points in each pair are joined by a chord.

Is it always possible to choose 100 pairs so that no chords intersect and the difference between the values in any one pair does not exceed 150?

See The Solution Submitted by Brian Smith    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
100% Solution | Comment 9 of 10 |
(In reply to 99% solution by Cory Taylor)

Excellent insight, Cory!
I don't see any holes in this.
I think that you have proved that at least one connection is always possible, because point between 51 and 150 will by this method be paired to a point that is noty between 51 and 150.
NICE WORK!

p.s. -- I think you just proved that the difference does not exceed 149.

Edited on November 5, 2018, 10:45 am
  Posted by Steve Herman on 2005-11-15 12:10:23

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