Imagine that you have three boxes, one containing two black balls, one containing two white balls, and the third containing one black ball and one white ball.
The boxes were originally labelled for their contents (BB - WW - BW) but someone has inadvertently switched the labels so that now every box is incorrectly labelled.
Without looking inside, you are allowed to take one ball at a time out of any box that you wish, and by this process of sampling, you are to determine the contents of all three boxes.
What is the smallest number of drawings needed to do this?
(In reply to
hi by Gale)
hey Gale, you are showing in your method that you are altogether making three drawings, 2 from the first box and then 1 from one of the remaining two and still you are writing that the answer is 4. anyways, i am sorry to say that the answer is not 4 but less, so now its time for you to guess :) No problem if you did not get it correct, try and you will.
re: hi
