Find the smallest positive integer n such that n has exactly 144 distinct positive divisors and there are 10 consecutive integers among them (Note: 1 and n are both divisors of n)
(In reply to
not any lower..........spoiler by Ady TZIDON)
50400 = 7(5^2)(2^5)(3^2) not 3^3
2 3 6 3 = 108 divisors
|
Posted by goFish
on 2006-02-20 16:04:37 |