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Power! (Posted on 2006-03-09) |
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For function M(x,y,z), where x, y, and z, are single-digit, positive integers, the following is true:
M(1,2,3)=32
M(3,2,1)=8
M(4,5,6)=245
M(6,5,4)=95
M(7,8,9)=800
M(9,8,7)=416
M(5,3,1)=15
M(1,3,5)=135
For what values of x,y,z, other than 1,3,5, does M(x,y,z)=100x+10y+z?
Solution
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First the function is M(x,y,z) = x + y^2 +z^3
no short cut or formal method(as i think) to get it just observe that x,y,z = 1,2,3 produces more value than x,y,z = 3,2,1 ...which means z has more impact than say x right ... as we see other values we can more or less work out the function
As for the question i used a program
values are
x= 1 y=3 z=5
x=1 y=7 z=5
x=5 y=1 z=8
x=5 y=9 z=8
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Posted by phi
on 2006-03-09 09:16:21 |
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