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Pythagorean Chain (Posted on 2006-03-20) Difficulty: 3 of 5
Take a right triangle with integer sides A, B, & C.
(C need not be the hypotenuse.)

To side C attach another right triangle with integer sides C, D & E.

On this new triangle attach another right triangle to either side D or E. Continue the process of attaching a new right triangle to the previous; creating a chain of right triangles.

Three further rules:
1. No side length may be repeated.
2. No triangles may overlap.
3. No side may have length over 10000.

How many triangles can you make in this chain?

See The Solution Submitted by Jer    
Rating: 3.5000 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts New Lower Limit | Comment 9 of 19 |
Well, 4 is certainly not the maximum chain length. Here's a 6 chain: 4-3-5 5-13-12 12-16-20 20-15-25 25-7-24 24-30-18 Note that I'm not close to the 10000 limit.  Seems to be room for a longer chain ... For instance, I can multiply the 6-chain by 3, and then attach a new triangle to the start of the chain, forming: 20-16-12 12-9-15 15-39-36 36-48-60 60-45-75 75-21-72 72-90-54 Voila!  A 7-chain Still seems to be a lot of room...

Edited on June 9, 2006, 6:14 pm
  Posted by Steve Herman on 2006-03-20 18:17:44

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