Determine all integer solutions (x,y,z) for the system of equations
x²z + y²z + 4xy = 40,
x² + y² + xyz = 20
I got z = 20/y^2-2 with x = y.
Since the only integer solutions of 20/y^2 are y^2 = 1 and y^2 = 4, this shows that the 4 answers found are unique.
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Posted by goFish
on 2006-03-31 06:43:27 |