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Hanoi Hard Hack (Posted on 2006-04-23) Difficulty: 3 of 5
In the standard Towers of Hanoi problem, you have three poles: the first has a pyramid of n disks, and the other two are empty. Your task is to move the disks to the third pole, with the restriction that you can move one disk at a time, never putting a larger disk on top of a smaller one.

How many moves would this task take, if ALL moves had to be either to or from the middle pole? (Thus, you cannot move a disk directly from the first pole to the third one, or viceversa.)

See The Solution Submitted by Old Original Oskar!    
Rating: 3.6667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re(2): Solution - R.T.Q. | Comment 4 of 8 |
(In reply to re: Solution by iamkobe)

Dej Mar and iamkobe are correct, and I did not read the question thoroughly. 

The correct solution is f(n) = (3^n)-1.

My initial post only considered moving the plates to the middle pole.  To get them to the furthest pole takes twice as many moves. Thus (3^n)-1 vice ((3^n)-1)/2.


  Posted by Leming on 2006-04-23 19:37:12
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