There is a rectangular tin 2cm by 3cm at the base, 2cm deep and open at the top.
It is filled with water to a depth of .4cm.
Twelve 1cm steel cubes are placed in the tin one by one. The first six form a single layer at the bottom. The next six form a second layer.
To what height does the water level rise after the placement of each cube?
Assume the cubes fit together tightly, leaving no spaces.
(In reply to
Solution by Dej Mar)
its the 6th cube that concerns me: if the water wouldnt overflow; wouldnt this 1cm³ of water be pressed together at a higher density? Allowing the 6th cube to go a little deeper than the top of the other 5? I think it has something to do with the body mass of steel? Too much pressure on the water and since steel doesnt flood in water, i think it will cause the water molecules to tighten up and as an effect of this, the bottom of the cube will be lower than the top of the others. Not much, but it should be a difference.
This would effect the water level after the placement of the 10th cube. But it would occur again with the placing of the 11th cube, and eventually the 12th as well.
And an other problem i have, is when you would put the first 4 cubes in a corner, and then the 5th in the middle, if you would put the 6th, i think it might tilt, it wouldnt be possible to put it exactly on top.
re: Solution
