A soldier has to check for mines a region that has the form of an equilateral triangle. Let h be the length of an altitude of the triangle and h/2 the radius of activity of his mine detector. If the soldier starts at one of the vertices of the triangle, find the length (in terms of h) of the shortest path he could use to carry out his task.
(In reply to
a shorter one :-) by Daniel)
I like it
it looks like the shortest, yet lacks a formal proof
re: a shorter one :-)
