A soldier has to check for mines a region that has the form of an equilateral triangle. Let h be the length of an altitude of the triangle and h/2 the radius of activity of his mine detector. If the soldier starts at one of the vertices of the triangle, find the length (in terms of h) of the shortest path he could use to carry out his task.
(In reply to
re: a shorter one :-) by Ady TZIDON)
yeah, I'm working on a formal proof, but I also have some other ideas that may result in yet shorter paths, so I'm waiting until I've researched all of them to really work on a formal proof.
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Posted by Daniel
on 2006-07-29 12:44:29 |
re(2): a shorter one :-)
