Find a number ABCDEFGHIJ, with all its digits different, such that:
- A, C, E, G, and I are odd
- HIJ is a multiple of BCD
- GH is a multiple of AB
- HIJ/BCD equals GH/AB
3218709654 works, though I'm not sure it's the only solution.
654/218 = 96/32 = 3
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Posted by Jyqm
on 2006-07-31 13:01:29 |