Find a number ABCDEFGHIJ, with all its digits different, such that:
- A, C, E, G, and I are odd
- HIJ is a multiple of BCD
- GH is a multiple of AB
- HIJ/BCD equals GH/AB
I crunched it out in mathematica fairly quickly and got this as the only solution
3218709654
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Posted by Daniel
on 2006-07-31 13:06:01 |