You have six balls - three red and three black. All the red balls weigh differently, i.e. one of them is heavy, the other medium, and the third light. Each red ball has a black twin of the same weight. A heavy and a light ball put together weigh as much as two medium balls.
What is the least number of weighings required on a balancing scale to determine which is which?
(In reply to
A different solution by gregg)
i think it requies only 2 tries.
2 R and 2 B
then in next try u can tell the exact ball
|
Posted by atul
on 2006-08-10 23:30:53 |