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Pandigital Sum (Posted on 2006-09-19)

Find a 2-digit integer, a 3-digit integer and a 4-digit integer, such that:

among them contain all digits 1 - 9

each integer is divisible by each of its digits

the sum of the three integers is a 4-digit number that is also divisible by each of its digits, which are all different as well

See The Solution Submitted by Charlie

Rating: 5.0000 (1 votes)

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Solution

| Comment 1 of 5

48 672 3195

Sum = 3915

The only solution to the puzzle.

Posted by Penny on 2006-09-19 07:54:02

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