In the ten problems listed below, your task is to make the number shown in bold, using once and once only, all six numbers, which accompany it.
You may use any mathematical operations you wish, to arrive at the given number.

            784 1, 1, 5, 6, 8, 100
            327 6, 7, 8, 9, 9, 50
            931 3, 4, 7, 8, 10, 75
            425 2, 4, 6, 8, 9, 50
            489 2, 3, 4, 6, 10, 75
            845 4, 7, 8, 9, 9, 25
            763 2, 3, 4, 5, 6, 25
            599 2, 3, 4, 6, 7, 75
            291 4, 8, 9, 9, 10, 100
            143 1, 4, 5, 6, 9, 10

Is more than one solution possible for a problem? Please include them if you find some.

784 = 6!+8^(SQRT(100/5^(1+1)))
327 = 6!-8*50+7+9-9
931 = (8+4)*75+(3+log(10))!+7
425 = 8*(6*9-4)+50/2
489 = 75*6+4!+10+2+3

And for the question:
Is more than one solution possible for a problem?

I'd say that since one can use infinitely many operations per problem there should be infinitely many ways to form different solutions.

Posted by atheron on 2006-10-31 17:46:03