You draw a square. Then, you draw the largest possible circle, tangent to all four sides. If the lower left corner of the square is at (0,0), and the sides of the square are parallel to the coordinate axis, the point (2,1) is on the circle, within the square.
What is the radius of the circle?
(In reply to
Solution by Jyqm)
If you take the center of the circle at (r,r), and the equation (x-r)^2 + (y-r)^2 = r^2, then you get two solutions, 5 & 1.
This happens a lot whn square roots are used in place a quadratic solution.
Edited on November 25, 2006, 7:49 am
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Posted by Kenny M
on 2006-11-25 07:47:54 |
re: Solution (other half)
