You draw a square. Then, you draw the largest possible circle, tangent to all four sides. If the lower left corner of the square is at (0,0), and the sides of the square are parallel to the coordinate axis, the point (2,1) is on the circle, within the square.
What is the radius of the circle?
I got the same answers, 1 and 5.
This is just because the line y= .5 x and the circle intersect at two points. When each point is alternately defined as (2,1), then r must be either 1 or 5, depending on which intersection point you're calling (2,1)
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Posted by Larry
on 2006-11-25 08:37:04 |