You draw a square. Then, you draw the largest possible circle, tangent to all four sides. If the lower left corner of the square is at (0,0), and the sides of the square are parallel to the coordinate axis, the point (2,1) is on the circle, within the square.
What is the radius of the circle?
(In reply to
re: Solution (other half) by Kenny M)
However, as Oskar mentioned, R=1 is not a valid solution, since in this case (2, 1) is the point where the circle is tangent with the right side of the square, so it's "on" the square and not "within" it.
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Posted by Jyqm
on 2006-11-25 10:16:16 |
re(2): Solution (other half)
