In triangle ABC, the perpendiculars from A to the internal bisectors of angles B and C meet those bisectors at X and Y. Prove that XY is parallel to BC.
(In reply to
re: Solution by Charlie)
I see that there are two right triangles sharing a base and having equal angles at the vertex, making their join an isosceles triangle.
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Posted by Charlie
on 2006-11-27 13:28:02 |