One equation with nine unknowns! (Posted on 2006-12-13)
Solve the given equation by using the integers from 1 to 9 inclusive exactly once each.
a/(b*c)+d/(e*f)+g/(h*i)=1
Note: Obviously this problem is easily susceptible to a brute force approach - however, it would be nice to see some arguments that don't use computer programs!
Since 5 and 7 are both relatively prime to all other digits between 1
and 9, I'll bet that they are both numerators. Without loss of
generality, let's say a = 5 and d = 7.
First little thought ...
