All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Logic
An Accommodation Problem (Posted on 2006-12-15) Difficulty: 3 of 5
Twelve people share six college rooms.

The names of the individuals, the available room numbers and the colour of each room are given below, albeit not in the same order.

Names of the individuals: Kenneth, Ted, Daphne, Sheila, Derek, Alexa, Diandra, Gene, Tyra, James, Sarah and Grant.

Available Rooms: #1, #2, #3, #4, #5, #6.

Room Colours: Blue, Green, Yellow, Orange, Pink and White.

Match each of the individuals with their roommates, room numbers and colour of their rooms.

It is known that:

(I) Kenneth and Ted share a room.
(II) Derek does not live in room #6, which is yellow.
(III) Neither room #5 nor room #4 is blue or orange.
(IV) The pink room has an odd number, but it is not #3.
(V) Alexa lives in room #5 with Sheila.
(VI) Diandra's roommate is not Tyra.
(VII) The blue room is even numbered.
(VIII) James lives in the green room; Sheila in the white one.
(IX) Sarah is not in room #3.
(X) Grant's room is not blue.

See The Solution Submitted by K Sengupta    
Rating: 2.1429 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Another assumption... | Comment 3 of 11 |
(In reply to Another assumption... by Avin)

I would like to clarify that the tenets corresponding to the problem requires one to match each of the individuals with their roommates.
Accordingly, there are precisely two persons per room.


  Posted by K Sengupta on 2006-12-15 11:28:11
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information